In the following reaction $C_{6}H_{5}CH_{2}Br \xrightarrow[(ii)H_{3}O^{+}]{(i)Mg, \text{Ether}} X$
Product $X$ is

  • A
    $C_{6}H_{5}CH_{3}$
  • B
    $C_{6}H_{5}CH_{2}OH$
  • C
    $C_{6}H_{5}CH_{2}CH_{2}C_{6}H_{5}$
  • D
    $C_{6}H_{5}CH_{2}OCH_{2}C_{6}H_{5}$

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